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EMF Equation of Transformer

EMF Equation of Transformer

Let
N1 = Number of turns in primary windings.    
N2 = Number of turns in second windings.
  • = Maximum flux in the core in Webbers.                                                   
  • m= Bm.A,
f = Frequency of A.C input in Hz.
As shown in fig- flux increases from its zero value to maximum value Øm  in one quarter of the cycle i.e. in ¼ second.
Average rate of change of flux = (Øm / ¼f.)
= 4f Øm Wb/s or volt.
 
Now rate of change of flux per turn means induced e.m.f in volts.
Average e.m.f /per turn = 4f Øm volt.
If flux Øm varies sinusoidally, then r.m.s value of induced .e.m.f is obtained by multiplying the average value with form factor.
Form factor =r.m.s value / Average value =1.11
r.m.s value of e.m.f/turn = 1.11. 4 f Øm= 4.44f Øm volt
now r.m.s value of the induced e.m.f in the whole primary winding.
=( induced e.m.f/turn) . number of primary turns
E1 = 4.44fN1 Øm………………………………………(1)
E1 = 4.44fN1BmA.    (Øm= BmA)
 
Similarly, r.m.s value of the e.m.f. induced in secondary is,
E2 = 4.44fN2 Øm
E2 = 4.44fN2BmA.    (Øm= BmA)…………..(2)
 
It’s seen from (1) and (2) that E1/N1=E2/N2= = 4.44f Øm.  It means that e.m.f/ turn is the same is the same in both the primary and secondary windings.
So in ideal Transformer on no-load, V1=E1 and E2=V2 where E2 is the terminal voltage.
By : Engr Wasim Khan
CopyRight @ http://www.electricaltechnology.org/

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2 comments

  1. It is really easy to understand the emf equation of a transformer. It is even easier to understand with the neat and clean diagram. Just like this post <a href="http://www.electricaleasy.com/2014/03/electrical-transformer-basic.html&quot; rel="nofollow"> Electrical Transformer</a>. Thanks for the post. 🙂

  2. How we find numerical question in this site.please tell me

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