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# Transformers MCQs With Explanatory Answers

## Transformers (MCQs With Explanatory Answers)

1. A Transformer is designed to be operated on both 50 & 60 Hz frequency.For the Same rating, which one will give more out put; when,

1. Â Operates on 50 Hz
2. Â Operates on 60 Hz

Answer:Â Â Â Â Â  1.Â Â  operates on 50 Hz Â
Suppose,
When Transformer operates on 50 Hz Frequency
Transformer = 100kVA, R=700â„¦, L=1.2 H, f= 50 Hz.
XL = 2Ï€fL = 2 x 3.1415 x 50 x 1.2 = 377 â„¦Â
impedance Z = âˆš (R2+XL2) = âˆš (7002 + 3772) = 795 â„¦Â
Power factor Cos Î¸ = R/Z = 700/795 =0.88 Â
Transformer Output (Real Power)Â
kVA x Cos Î¸ = 100kVA x 0.88
Â 88000 W = 88kW
Now,
When Transformer operates on 60 Hz Frequency
Transformer =100kVA, R=700â„¦, L=1.2 H, f= 60 Hz.
XL = 2Ï€fL = 2 x 3.1415 x 60 x1.2 = 452.4 â„¦Â
impedance Z = âˆš (R2+XL2) = âˆš (7002 + 452.4 2) = 833.5 â„¦Â
Power factor = Cos Î¸ = R/Z = 700/833.5 =0.839
Transformer Output (Real Power)
kVA x Cos Î¸ 100kVA x 0.839
=83900W = 83.9kW Output
Now see the difference (real power i.e., in Watts)
88kW- 83.9kW = 4100 W = 4.1kW
If we do the same (As above) for the power transformer i.e, for 500kVA Transformer, the result may be huge, as below.
(Suppose everything is same, without frequency)
Power Transformer Output (When operates on 50 Hz)Â
500kVA x 0.88 = 44000 = 440kW
Power Transformer Output (When operates on 60 Hz)
500kVA x 0.839 = 419500 = 419.5kW
Difference in Real power i.e. in Watts
440kW â€“ 419.5kW = 20500 = 20kVA

2. In a Transformer , The primary flux is always _________ the secondary ( flux).

1. Greater then
2. Smaller then
3. Equal
4. Equal in both step up and Step down Transformer

Answer:Â Â Â  4.Â Â Â  Equal in both step up and Step down Transformer
Flux in Primary and Secondary Winding is always equal.
Explanation:
Given Data;
Primary Number of Turns N1 = 524,
Secondary Number of Turns N2 = 70
Primary Input Voltage V1= 3300 Volts.
Secondary Current I2= 250 A.
Find/Calculate?
Secondary Voltage V2 =?
Primary Current I1=?
Â Î¦m 1 = Î¦m2
We Know that,
N2/N1 = V2/V1 ====> V2 = (N2 x V1)/N1
Putting the Values
V2 = (70 x 3300)/525 = 440 Volts Ans.
Now if Neglecting Losses,
V1I1= V2I2 ====> I1/I2 = V2/ V1 â€¦..Or…..I1 = (V2 x I2) / V1
Putting the Values,
I1 = 440 x 250/3300 = 33.3 Amp Ans.
Now turn around the Transformer equation.
E1 = 4.44 f N1 Ï†m1
Ï†m1 = E1 / 4.44 f N1
Putting the Values
Î¦m 1 = 3300 / (4.44 x 50 x 525) = 0.0283 Weberâ€™s
Î¦m 1 = 28.3mWeberâ€™s = Flux in Primary Windings
Same is on the other side,
E2 = 4.44 f N2 Ï†m2
Î¦m2 = E2 / 4.44 f N2
Putting the values,
Î¦m2 = 440 / (4.44 x 50 x 70) = 0.0283 Weberâ€™s
Î¦m2 = 28.3mWeberâ€™s = Flux in secondary Windings
So You can see the flux (Î¦m) produced in Both Primary and Secondary Winding is same.

3. What would happen if we operate a 60 Hz Transformer on 50 Hz Source of Supply.(and how can we do that?

1. Current will decrease (so increase the current)
2. Current will increase ( so decrease the current)
3. Current will be same in both cases.
4. No Effect ( We can do that without changing anything)
5. Â We can’t perform such an operation.

Answer:Â Â Â Â  2.Â Â Â Â  Current will increase ( so decrease the current)
Explanation:Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Suppose this is a 60 Hz transformer

4. A Step-Up Transformer which has 110/220 turns.What would happen if we replace it with 10/20 turns? (because Turns ratio would be same in both cases)Â

1. induced E.M.F wold be same
2. Induced E.M.F would be decreased

Ans:Â Â Â  2.Â Â  Induced E.M.F would be decreased
Explanation:
Click image to enlarge

5. The rating of transformer may be expressed in ____________.

1. kW
2. kVAR
3. kVA
4. Horse power.

Answer:Â Â Â  3.Â Â  kVA
Explanation:
There are two type of losses in a transformer;
1. Copper Losses
2. Iron Losses or Core Losses orÂ  Insulation Losses
Copper losses ( IÂ²R )depends on Current which passing through transformer winding while Iron Losses or Core Losses orÂ  Insulation Losses depends on Voltage.
That’s why the rating of Transformer is in kVA,Not in kW.

6. What will happen if the primary of a transformer is connected to D.C supply?

1. Transformer will operate with low efficiency
2. Transformer will operate with high efficiency
3. Â No effect
4. Transformer may start to smoke and burn

Answer:Â Â Â  4.Â Â  Transformer may start to smoke and burn.
Explanation:

7. What would happen if a power transformer designed for operation on 50 Hz (frequency) were connected to a 500 Hz (frequency) source of the same voltage?

1. Â Current will be too much high
2. Â Transformer may start to smoke and burn
3. Â Eddy Current and Hysteresis loss will be excessive
4. Â No effect

Answer:Â Â Â  3.Â Â Â  Eddy Current and Hysteresis loss will be excessive
Explanation;

8. What would happen if a power transformer designed for operation on 50 Hz (frequency) were connected to a 5 Hz (frequency) source of the same voltage?Â

1. Â Current will be too much low
2. Â Transformer may start to smoke
3. Â Eddy Current and Hysteresis loss will be excessive
4. Â No effect

Answer:Â Â Â  2.Â Â Â  Transformer may start to smock
Explanation:Â
9. A Step Up transformer _____________.Â
1. Step Up the level of Voltage
2. Step down the level of current
3. Step up level the power
4. Step up the level of Frequency
5. 1 and 2 only

Answer:Â Â  5.Â Â  1 and 2 only.
Explanation:
A Step up transformer only step up the level of voltage and step down the level of current.
because the input power is same.
So according to P=VIâ†’ I = P/V…. We can see that, when Voltage increases, current decreases.
So in Step up transformer, input power is same, therefore, when voltage increases, then current decreases.

10. Under what condition is D.C supply applied safely to the primary of a transformer?Â

1. We can connect directly to DC. No condition required
2. We can’t connect to DC Supply
3. A High resistance should be connect in series with primary, but circuit will be useless.
4. Â The above statement is wrong

Answer:Â Â Â  3.Â Â Â  A High resistance should be connect in series with primary, but circuit will be useless.
Explanation:

11. An Auto-transformer (which has only one winding) may be used as a ______?

1. Step-Up Transformer
2. Step-Down Transformer
3. Both Step-Up and Step-Down transformer
4. None of the above

Answer:Â Â Â Â Â  3.Â Â Â  Both Step-Up and Step-Down transformer
Explanation:

12.Â  E.M.F Equation of the Transformer is _________.

1. E1 = 4.44 f N1 Ã˜m Â Â  Â  ,Â  Â  E2=4.44 f N2 Ã˜mÂ
2. E1= 4.44 f N1 Bm A Â  , Â  E2 = 4.44 f N2 BmAÂ
3. E1=Â  4.44 N1 Ã˜m/TÂ  Â Â  , Â Â  E2=4.44 N2 Â Ã˜m/TÂ
4. All of the aboveÂ
5. None of the above

Answer:Â Â Â Â Â Â Â Â Â Â Â Â  4.Â Â Â Â Â Â  All of the above
Explanation:
Take the basic Equation of the transformer (Option 1) E1 = 4.44 f N1 Ã˜m Â Â  Â  ,Â  Â  E2=4.44 f N2 Ã˜m ,Â
and then, first put the value ofÂ  Ã˜m = Bm A. So the equation becomes as in Option 2.
Now put the value of Frequency ( f = 1/T ) in Equation on Option (1). So the equation becomes as in Option 3.

13. The friction losses inÂ  Real Transformers are _________?

1. 0%Â
2. 5%Â
3. 25%
4. 50%

Answer:Â Â Â Â Â Â Â Â Â  1.Â Â Â Â Â Â Â  0%
Explanation: Transformer is a Static Devise. So, no rotation, No Friction losses.

14.Â  In Three Phase Transformer, The load Current is 139.1A, and Secondary Voltage is 415V. The Rating of the Transformer would be ___________.

1. 50kVAÂ
2. 57.72kVAÂ
3. 100kVAÂ
4. 173kVA

Answer:Â Â Â Â Â Â Â  3.Â Â Â Â Â  100kVA
Explanation:
Rating of a Three Phase Transformer:
P = âˆš3. V x I
Rating of a Three phase transformer in kVA
kVA = (âˆš3. V x I) /1000
Now
P = âˆš3 x V x I (Secondary voltages x Secondary Current)
P= âˆš3 x 415V x 139.1A = 1.732 x 415V x 139.1A= 99,985 VA = 99.98kVA=100kVA
For more Detail
How to Calculate/Find the Rating of Transformer (Single Phase and Three Phase)?

15Â  In Single Phase Transformer, The Primary Current and Primary Voltage is 4.55 and 11kV respectively. The Rating of the transformer would be________?

1. 50kVAÂ
2. 86kVAÂ
3. 100kVAÂ
4. 150kVA

Answer:Â Â Â Â Â Â Â  1.Â Â Â Â Â  50kVA
Explanation:
Rating of a Single Phase Transformer:
P =Â  V x I
Rating of a Single phase transformer in kVA
kVA = (V x I) /1000
Now
P =Â  V x I (Primary voltages x Primary Current)
P =Â  11000V x 4.55AÂ  = 50,050VA = 50 kVA
For more Detail .. Read the rating of transformer post in MCQs No 14 explanatory section titled as
“How to Calculate/Find the Rating of Transformer (Single Phase and Three Phase)”?

16.Â  An Isolation Transformer Has Primary to Secondary turns ratio of __________.

1. 1 : 2 Â
2. 2 : 1Â
3. 1 : 1Â
4. Can be any ratio

Â Answer:Â Â  3.Â Â Â  1:1
Explanation: Isolation Transformer is used for isolation purpose only. Isolation transformer transfer electrical power from the source circuit to another circuit with connecting electrically (but magnetically) for preventing electric shock and also used in sensitive devices (like medical equipment etc). Thus, isolation between two electrical circuit can be done by Isolation transformer with turns ratio of 1:1.

17.Â Â  In an Auto Transformer, The Primary and Secondary are__________Coupled.

1. Only Magnetically
2. Only Electrically
3. Magnetically as well as Electrically
4. None of the above

Answer:Â Â Â Â  3.Â Â Â  Magnetically as well as Electrically
Explanation: As we know that in a Transformer, Primary and Secondary winding are magnetically coupled. But in case of Auto transformer, there is only one winding (which is used both as a Primary and Secondary). Thus, in an In an Auto Transformer, The Primary and Secondary are Magnetically as well as Electrically Coupled.
for More detail: Check MCQs No 11 with diagram.

18.Â Â  A Transformer______________.

1. Changes ac to DC
2. Changes dc to AC
3. Steps up or down DC Voltages & Current
4. Steps up or down AC Voltages & Current

Answer:Â Â Â Â Â Â  4.Â Â Â Â  Step up or Step down AC Voltage & Current
Explanation:Â A Transformer does not work on DC and operates only and only on AC, therefore it Step up of Step down the level of AC Voltage or Current.
For More detail: Check MCQs No 9

19.Â Â  Transformer is a device which:________________.

1. Transfer Electrical power from one electrical circuit to another Electrical circuit
2. Itâ€™s working without changing the frequency
3. Work through on electric induction.
4. When, both circuits take effect of mutual induction
5. Can step up or step down the level of voltage.
6. Its Working withoutÂ  changing the Power.
7. All of the above

Answer:Â Â Â Â Â Â  7.Â Â Â Â  All of the above
Explanation: Transformer

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## Difference Between MCB & MCCB According To IEC Standards

MCB or MCCB – Difference in IEC Standards (IEC 60898-1 & IEC 60947-2) Circuit breakers …

1. i am Arvind garg.i am btech electrical engineer. i want to take knowledge of electrical.

• Dear Arvind Garg @ Stay tune to this blog. We update the blog on daily basis. Thanks

• A.O.A.
I am a electrical engineer.Your forum is very informative related to electrical.I want ask question related to OP-AMP IC,Why inductors are not fabricated in op-amp IC?Howkind of you!!!!

2. It is a very useful post. This quiz is very helpful for enhancing basic knowledge. I would like to suggest you to post a quiz related to induction technology. It would be very useful for gaining knowledge about induction technology and its applications.

3. sir, i have a question, If for the given rating and leakage reactance of a three phase transformer if cross section area of core is increased then wat is the effect on the core and copper losses. plz ans thank u sir<br />

4. i am pursuing btech electrical and want to know about softwares which will help me in future and which r crucial for me…suggest me some..!

5. i am associate engineer in electrical technology i wana to gain knowledg from u send u r e mail id thx<br />

6. Which circuit gives by airgap in instrument?

7. I have a doubt in question no. 4. How could we take the same flux when there are 10 turns. If our input voltage is fixed then we have to find out flux for the particular turns and this flux will be used to determine induced voltage V2. So the induced EMF would be same.<br />

• No… You can see the solved example in explanatory answer…practically, we have tried the circuit and the same result obtained as given in explanatory answer.. Thanks.

• yes sir i too have the same doubt….when you reduce the turns to maintain the same ratio….the flux is proportional to turns and should decrease according to the turns…simply i want to say that the flux induced due to 110 turns should not be equal to flux induced due to 10 turns…that would violate the law that flux is proportional to no of turns.

• Just check again…We can not use 10 turns instead of 110 turns… As EMF is directly proportional to the induced flux and we know that flux is also increases when turn increases.

• @ D Chowdhury : Flux established in the core is proportional to the applied voltage. Induced voltage in the winding is proportional to no. of turns and rate of change of flux. So if no. of turns is reduced keeping applied voltage constant the induced voltage reduces.

8. i have a doubt.the primary flux which is linked to secondary windings via core ,which has some reluctance .therefore the secondary flux is less than primary flux in non ideal case.

• Yes! here we talking about ideal case..

9. Thanks for the information. I found these questions really helpful and interesting which made me to read it again and again. Transformer is an electrical device that makes the transfer of energy by forming inductive coupling between the winding of its circuits. If you are interested in transformer you may visit <a title="Important Questions of Transformer" href="http://blog.oureducation.in/

10. i have a small dOubt abOut star-Delta cOnnections in tansfOrmer,<br />that Delta-Delta is pOssible or nOt then why they cant be used….

11. sir<br />we use fuses on the primary side of domestic transformer where 11kv line is connected.<br />but if load is increased on the secondary side of transformer then how these fuse will work which r connected on the primary side.because power on side is same ….plz ans

• Fuse wire depends on Current…Not on Power..

12. Abubakar Butt

very informative knowldge

13. 3 phase transformer main v and i ka phase angle nai lagy ga ?<br />Please tell me ?<br />kya hum ye formula nai laga saqty P=3*v*i* cos pie ?

14. JazakAllah Kheran

• We are working on it.. It will be live ASAP. Thanks

• Answers are not visible. kindly help.

• Click the “Show Explanatory Answer” below each MCQs for Explanatory Answers. let me know if you face any prob. thanks

16. i also cant see the answer and explanation plzz help me too.

Am B-tech Electrical engineer. Am preparing for interview but I’ve got problem that the answers of transformers MCQs are not showing please check and tell me that the issue is on your side or mine. waiting for quick response.

18. sir may i request some ebook of TESLA COIL or about wireless energy transmission… thankyou verrymuch in advance… hehe

19. praveen kumar

Vry nice site sir,

I am really impressed

20. Sir,
In questn no 4, you explained that flux can be calculated through no of turns and input voltage.But as we know the common transformer equation that N1/N2=E1/E2.Through this case this equation is going to be not usefull as the flux is decreased and input voltage is remaining same.In example you have taken input voltage lower then the first so this will in turn reduce flux but we are not decreasing our input voltage so equation must be followed.Please explain this case briefly
Thank you

21. i find your blog very interesting and useful regarding all the electrical stuff and calculation and relation and wiring have been done perfectly well and good ..

22. Shubham Ghore student

Sir pl explain per unit impedance of transformer and utility of mentioning it in the name plate of a transformer .