*Explain the statement that ” In Inductive circuit, when Inductance (L) or inductive reactance (X*

_{L}) increases, the circuit Current (I) decrease”**OR**

*Why the circuit Current (I) decrease, when Inductance (L) or inductive reactance (X*

_{L}) increases in inductive circuit?__Explanation:__

We know that, I = V / R,

but in inductive circuit, I = V/X_{L}_{So Current in inversely proportional to the Current ( in inductive circuit.}_{Let‘s check with an example.. }*Suppose, when Inductance (L) = 0.02H*

X_{L} = 2πfL = 2 x 3.1415 x 50 x 0.02 = 6.28 Ω

^{2}+X

_{L}

^{2}) = √ (10

^{2}+ 6.28

^{2}) = 11.8 Ω

*Now we increases Inductance (L) form 0.02 H to 0.04 H,*_{L}= 2πfL= 2 x 3.1415 x 50 x 0.04 = 12.56 Ω

^{2}+X

_{L}

^{2}) = √ (10

^{2}+ 12.56

^{2}) = 16.05 Ω

**Conclusion**:

*Hence proved,*_{L}increases, the circuit current decreases, and Vice Virsa.

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Welcome Dear

bhut achhe yaar……….<br />mujhe ak aue baat puchhni hai aapse mera no.9772141132<br />apko waqt mile to jaroor misscall dijeeyega

Thanks Dear

Hello,

thank u for valuable informatin.

my query is,

why we dnt use below 50 Hz in e-machines?

Pls give answer.