fbpx
AC FundamentalsAlternating CurrentBasic / Important Electrical FormulasEE Questions / AnswersSingle Phase AC Circuits

Why the Circuit Power factor (Cos θ) Decreases, when Inductance (L) or inductive reactance (XL) increases, In inductive circuit?

 Why the Circuit Power factor  (Cos θ) Decreases, when Inductance (L) or inductive reactance (XL) increases, In inductive circuit?
OR
Explain the statement that  “ the Circuit Power factor  (Cos θ) Decreases, when Inductance (L) or inductive reactance (XL) increases”

Explanation:  
Suppose, 
when Inductance (L) = 0.02H

V=220, R= 10 Ω, L=0.02 H, f=50Hz.

XL = 2πfL = 2 x 3.1415 x 50 x 0.02 = 6.28 Ω

Z = √ (R2+XL2) = √ (102 + 6.282) = 11.8 Ω
Cos θ = R/Z = 10/11.05 = 0.85
 
Now we increases Inductance (L) form 0.02 H to 0.04 H,
V=220, R= 10 Ω, L=0.04 H, f=50Hz.
XL = 2πfL= 2 x 3.1415 x 50 x 0.04 = 12.56 Ω
Z = √ (R2+XL2) = √ (102 + 12.562) = 16.05 Ω
Cos θ = R/Z = 10/16.05 = 0.75
 
Conclusion:

We can see that, When inductance (L) was 0.02, then circuit current were 18.64 A, and Circuit power factor was (Cos θ) = 0.85.

But, when Circuit inductance increased from 0.02H to 0.04 H, then  Power Factor (Cos θ) decreased from 0.85 to 0.75.

Hence proved,

In inductive circuit, when inductive reactance XL increases, the circuit power factor also Decreases.

Show More

Electrical Technology

All about Electrical & Electronics Engineering & Technology. Follow , Twitter , Instagram, Pinterest, YouTube, & Linkedin to get the latest updates or subscribe Here to get latest Engineering Articles in your mailbox.

Leave a Reply

Your email address will not be published. Required fields are marked *

Back to top button
Close
Close

Adblock Detected

Please consider supporting us by disabling your ad blocker