# How to Calculate the Number of Fluorescent Lamps in a Final Sub Circuit?

## How to Determine the Number of Fluorescent **Tubelight** and CFL Lamps in a Final Sub Circuit?

The number of fluorescent lamps, tube lights and compact fluorescent light (CFL) is not equal to the number of incandescent lamp having the same power rating. This is due to the rule of chock and ballast in the fluorescent tube circuit. Chock and ballast acts as a controller device and power factor decreased due to the inductance of the chock. Capacitors are used to improve the power factor and overall current of the circuit increases as compared to the incandescent lamps.

Now suppose, We have to install 75 Watts fluorescent lamps instead of incandescent lamp for general lighting.

If the current rating of the final sub circuit is 5 Amperes having supply voltage of 220V (110-120V in US), then the number of flourcent lamps can be find by the following formula.

Supply Voltage x Current Rating of Sub-Circuit / (2 x Power Rating of Fluorescent Lamps in Watts)

220V x 5A / (2 x 75W)

**= 7.33**

It means, **you can use 7 numbers of fluorescent lamps **or tube lights each of having 75W on 5A, 220V final sub circuit.

In case of 40W tube lights where the supply voltage is 120V and current rating of final sub-circuit is 10A.

120V x 10A / (2 x 40W)

**= 15**

Hence, **you can install the maximum of 15 number of florescent tube lights** on a final sub-circuit having 10A and 120V AC supply.

Note:

- Final sub-circuits based on max demand i.e. it consumes max power while appliances are in use.
- Power factor has been consider due to the inductive load (chock and ballast) in fluorescent lamps circuits.

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When we want to connect both Lamp & Fluorescent Lamps in final sub circuit what will be the formula?

If you want to install both kind of lamps… Simply use

(Supply voltage * current rating of the sub circuit) / ((2* power of fluorescent lamps)+ power of incandescent lamps)

i.e. use the highest power rating.

There will be 14 lamps of 75W.

I=P/V=(14*75)/220=4.77 A, as the choke only ignite the tube.

Dear I Appreciate you, I Have the same answer, why electrical technology write 7. don.t know

why we multiply 2 with power of lamps in upper formula?

Kitchen electronic appliances check by multi meter and many part how defect parts how check maximum defected part

Why are you multiplying the bulb wattage by 2 IF you are calculating the number of bulbs

This is due to chock / ballast used in the CFL circuit which need more power than simple resistive circuit of Incandescent lamp.