## A (50/60 Hz) Transformer. Which one will give more Output?

A Transformer is designed to be operated on both 50 & 60 Hz frequency. For the Same rating, which one will give more out put; when,

- Operates on 50 Hz
- Operates on 60 Hz

**Obviously!** It will give more out put when we operate a transformer (of same rating) on 50 Hz instead of 60 Hz.

Because in previous posts, we proved that, in inductive circuit, when frequency increases, the circuit power factor decreases. Consequently, the transformer out put decreases.

Let’s consider the following example.

*Suppose,**When Transformer operates on 50 Hz Frequency*

**Transformer = 100kVA, R=700**

**Ω**

**, L=1.2 H, f= 50 Hz.**

X

_{L}= 2πfL = 2 x 3.1415 x 50 x 1.2 = 377 ΩImpedance Z = √ (R

^{2}+X_{L}^{2}) = √ (700^{2}+ 377^{2}) = 795 ΩPower factor Cos θ = R/Z = 700/795 =0.88

Transformer Output (Real Power)

kVA x Cos θ

100kVA x 0.88

88000 W = 88kW

*Now,**When Transformer operates on 60 Hz Frequency*

**Transformer =100kVA, R=700**

**Ω**

**, L=1.2 H, f= 60 Hz.**

X

_{L}= 2πfL = 2 x 3.1415 x 60 x1.2 = 452.4 ΩImpedance Z = √ (R

^{2}+X_{L}^{2}) = √ (700^{2}+ 452.4^{2}) = 833.5 ΩPower factor = Cos θ = R/Z = 700/833.5 =0.839

Transformer Output (Real Power)

kVA x Cos θ

100kVA x 0.839

=83900W = 83.9kW Output

Now see the difference (real power i.e., in Watts)

88kW- 83.9kW = 4100 W = 4.1kW

*If we do the same (As above) for the power transformer i.e, for 500kVA Transformer, the result may be huge, as below.*(Suppose everything is same, without frequency)

Power Transformer Output (When operates on 50 Hz)

500kVA x 0.88 = 44000 = 440kW

Power Transformer Output (When operates on 60 Hz)

500kVA x 0.839 = 419500 = 419.5kW

Difference in Real power i.e. in Watts

440kW – 419.5kW = 20500 = 20kVA

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Wrong unit in the last row!<br />440kW – 419.5kW = 20500W = 20kW

20500W … We assume that 20.5kVA = 20kVA … for calculation purpose only ….

How to calculate the induction value resistance value and amps value of transformer and how calculate the winding turns based on voltage

Thanks to give basic and extra knowlege.