# Can We Replace a 110/220 Turns Transformer with 10/20 Turns?

**1:2 Turn Ratio for 110:220? The Turn Ratio is Same, Shall its Rating be Same?**

A step up transformer which has 110/220 turns. Can we replace it with 10/20 turns or 1:2? Turns ratio is same, shall its rating be same? Give appropriate reasons?

No. Because we know that flux is directly proportional to the ampere turns (**Φ ∝ At)**. So if we reduce the number of turns i.e. turns ratio, flux will be also reduced which leads to reduce the induced EMF because EMF is directly proportional to the flux (**EMF ∝ Φ**). If we go about the transformation formula, the calculated value may be right but if we use the EMF equation of the transformer, it shows a different story. Let’s see what happens when we reduce the number of turns in the transformer windings.

**Transformer Rating & Parameters**

- N
_{1}= 110 Turns - N
_{2}= 220 Turns - E
_{1}= 220V - Flux = Φ
_{m}= 9.01 mW (mille Weber) - E
_{2}= ?

**When Turn Ratio is 110/220**

To find E_{2}, we know that

E_{2}/E_{1} = N_{2}/N_{1}

E_{2} = (N_{2}/N_{1}) x E_{1}

Putting the values

E_{2} = (220/110) x 220V

E_{2} = 440V

**When Turn Ratio is 10/20**

Now, if we use 10/20 Turns ratio instead of 110/220.

E_{2} = (N_{2}/N_{1}) x V1

E_{2} = (20/10) x 220V

E_{2} = 440V

**We can see that the value of step up voltage is same in both case whether we use 10/20 or 110/220 turns.**

But I’m lying. It’s not true.

Let’s turn around to the EMF equation of the transformer.

**E**_{1}** = 4.44 x ****f**** x N**_{1}** Φ**_{m }_{……….. (Primary) }

**E**_{2}** = 4.44 x ****f**** N**_{2}** Φ**_{m }_{……….(Secondary) }

**In case of turn ratio of 110/220**

**E**_{1}** = 4.44 x ****50**** x 110 x **9.01 mW_{ }

E_{1} = 220V

**E**_{2}** = 4.44 x ****50 x**** 220 x **9.01 mW_{ }

E_{2} = 440V

**In case of turn ratio of 10/20**

**E**_{1}** = 4.44 x ****50**** x 10 x **9.01 mW_{ }

E_{1} = 20V

**E**_{2}** = 4.44 x ****50 x**** 20 x **9.01 mW_{ }

E_{2} = 40V

Hmm. That is a huge different. That’s why we can’t use 10/20 turns ratio instead of 110/220 because flux is directly proportional to the ampere turns (**Φ** **∝ At**). If we reduce the number of turns (turns ratio of the transformer), the amount of produced flux will be reduced because of lower ampere turns which causes to reduce the amount of inducted EMF too i.e. induced EMF is directly proportional to the flux (**Φ ∝ EMF**).

In short, If we reduce the turn ratio of a transformer from 110/220 to 10/20 or 1:2, The following may occurs.

- The current in the primary winding of the transformer may increase due to reduced amount of impedance (Z) and resistance (R) i.e. low turns means low inductive reactance (X
_{L}) where X_{L}dependents on the inductance of the turns. - There may be high power loss due to high current in the primary as well as high power loss (I
^{2}R) which may leads to burn the primary windings of the transform. - The induced EMF will be reduces as well due to low magnetic flux which depends on the number of coil turns.

Related Post: Why Transformer Rated In kVA, Not in KW?

Good to Know

- Transformer ratio of
**2:1**is not the same as**1:2**. - Transformer
**turn ratio**of**2:1 means this is a step down transformer**. - similarly, turn ratio of
**1:2 shows a step up transformer**. - Turn ratio of 2:1 indicate that there are two turns in the transformer primary for the single turn in the secondary winding.
- In addition, turn ratio of
**1:2 shows that if there are 1V in the primary**, the voltage in the secondary would be 2V. **Flux is directly proportional to the Ampere-Turns (At)**, not proportional to the**turns ratio (N)**.- In a
**2:1 transformer ratio**, if the current in the**primary is 2A and 1A in the secondary**, we are having**2 ampere turns (At) in the primary and 1 At in the secondary**. - Flux in the Primary and Secondary Winding of a transformer is always same.
**Transformer**does not change the value of**power**,**frequency**,**flux**but only and only step up or step down the level of**AC voltage or current**(i.e.**transformer won’t operate on DC**).- In short, if we
**reduce the number of turns**(i.e. replacing 110/220 with 10/20), there will be**insufficient flux**in the core of transformer which will not work according to the rated parameters and design.

- Related Posts:
- How Find the Rating of Transformer in kVA (Single Phase and Three Phase)?
- Transformer Phasing: The Dot Notation and Dot Convention
- Transformer Efficiency, All day Efficiency & Maximum Efficiency
- TRANSFORMER NAMEPLATE (GENERAL REQUIREMENTS).

Conceptual….thanks for providing the info…

No of turns is inversely proportional to flux. Firstly N1/N2= E1/E2 so since the turns ratio is same in both the cases so E1 and E2 should be same. Now what happens is that…to maintain the same potential E1 when N1=10, the flux increases. This is from the relation E1 is directly proportional to N1* flux. Since N1 reduces so flux increases to keep.

the point i need the modified value of flux corresponding to N1=10….since N1 decreases from 110 to 10 keeping the turn ratio(N2/N1) same….so the flux must correspondingly increase to a value of 0.099… Putting the new value of flux and N1 in eqn E1= 4.44f N1* flux..we get same value as before. This is due to the inverse relation between N1 and flux…E1(as got from emf.

The value for flux= 0.0091 that u used applies to the turns ratio 110/220 and not for the ratio 10/20. The value of flux for 20/10 is different.If u use the updated value for flux in the emf equation for 10/20 u will get the answer. New value of flux= 0.09909 for ratio 20/10…soE1= 4.44 * 50*10*0.09909….solving this gives E1=220 V for ratio 10/20.

Thank you Sir, because this question is my favorite question science 4th semesters diploma in electrical engineering, sbte Bihar